Respuesta :
Answer:
The p-value of the test is approximately 0.
Explanation:
The hypothesis can be defined as:
H₀: The proportion of TV sets tuned in to the show is not less than 20%, p ≥ 0.20.
Hₐ: The proportion of TV sets tuned in to the show is less than 20%, p < 0.20.
Given:
[tex]n=5000\\\hat p=0.15\\\alpha =0.01[/tex]
The test statistic is:
[tex]z=\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}} }=\frac{0.15-0.20}{\sqrt{\frac{0.20(1-0.20)}{5000} }}= -8.77[/tex]
The p-value of test is:
[tex]p-value=P(Z<-8.77)\approx0[/tex]
*Use a standard normal table.
Thus, the p-value of the test is approximately 0.
