Answer:
4.14 cm.
Explanation:
Given,
For Coil 1
radius of coil, r₁ = 5.6 cm
Magnetic field, B₁ = 0.24 T
For Coil 2
radius of coil, r₂ = ?
Magnetic field, B₂ = 0.44 T
Using formula of maximum torque
[tex]\tau_{max}= NIAB[/tex]
Since both the coil experience same maximum torques
now,
[tex] NIA_1B_1 = NIA_2B_2[/tex]
[tex]A_1B_1 = A_2B_2[/tex]
[tex] r_1^2 B_1 = r_2^2 B_2[/tex]
[tex] 5.6^2\times 0.24= r_2^2\times 0.44[/tex]
[tex]r_2 = 4.14\ cm[/tex]
Radius of the coil 2 is equal to 4.14 cm.