as 100 milliliters of 0.10 molar KOH is added to 100 milliliters of 0.10 molar HCL at 298 K, the pH of the res?A. decrease to 3B. decrease to 4C. increase to 7D. increase to 13

Respuesta :

Answer:

C. increase to 7.

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

[tex]KOH+HCl\rightarrow KCl+H_2O[/tex]

Thus, the molar relationship is 1 to 1, therefore, the moles are:

[tex]n_{HCl}=0.1mol/L*0.1L=0.01molHCl\\n_{KOH}=0.1mol/L*0.1L=0.01molKOH\\[/tex]

Thus, since the entire hydrogen ions are neutralized, the pH C. increase to 7.

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