This is an incomplete question, here is a complete question and image is also attached below.
How much longer is the hypotenuse of the triangle than its shorter leg?
a. 2 ft
b. 4 ft
c. 8 ft
d. 10 ft
Answer : The correct option is, (b) 4 ft
Step-by-step explanation:
Using Pythagoras theorem in ΔACB :
[tex](Hypotenuse)^2=(Perpendicular)^2+(Base)^2[/tex]
[tex](AB)^2=(AC)^2+(BC)^2[/tex]
Given:
Side AC = 6 ft
Side BC = 8 ft
Now put all the values in the above expression, we get the value of side AB.
[tex](AB)^2=(6)^2+(8)^2[/tex]
[tex]AB=\sqrt{(6)^2+(8)^2}[/tex]
[tex]AB=10ft[/tex]
Now we have to calculate the how much longer is the hypotenuse of the triangle than its shorter leg.
Difference = Side AB - Side AC
Difference = 10 ft - 6 ft
Difference = 4 ft
Therefore, the 4 ft longer is the hypotenuse of the triangle than its shorter leg.
