Respuesta :
Answer:
1) For this case we can use the absolute value and we can write the limit with this expression:
[tex] |T-38| \leq 2[/tex]
Where T represent the temperature for the refrigerator in F.
2) If we solve for T we have this:
[tex] -2 \leq T-38 \leq 2[/tex]
We can add 38 in all the sides of the inequality
[tex] -2+38 \leq T\leq 2+38[/tex]
And finally we got:
[tex] 36 \leq T \leq 40[/tex]
So then the refrigerator can work between 36 F and 40 F for this case.
Step-by-step explanation:
For this case we know that the refrigerator hould be set at 38 F, and the allowance or the variation is 2F.
Part 1
For this case we can use the absolute value and we can write the limit with this expression:
[tex] |T-38| \leq 2[/tex]
Where T represent the temperature for the refrigerator in F.
Part 2
If we solve for T we have this:
[tex] -2 \leq T-38 \leq 2[/tex]
We can add 38 in all the sides of the inequality
[tex] -2+38 \leq T\leq 2+38[/tex]
And finally we got:
[tex] 36 \leq T \leq 40[/tex]
So then the refrigerator can work between 36 F and 40 F for this case.
