Answer:
0.588 m/s forward
Explanation:
From the law of conservation of momentum, the sum of initial and final momentum are equal hence for this case, it will be expressed as
[tex]m_bu_b+m_mu_m=m_bv_b+m_mv_m[/tex]
Where m represnt mass, u and v represent initial and final velocities respectively, subscripts b and m represent ball and man respectively.
Since rhe man is initiallh at rest, then his initial velocity is zero.
Taking the forward direction as positive then backward direction when a ball bounces will be negative.
Substituting the mass of ball and man with 5 kg and 85 kg respectively, the initial velocity of ball with 8 m/s while final ball velocity as -2 m/s then we get
5*8+(85*0)=5*-2+(85v)
85v=50
V=0.5882352941176
Rounding off, the velocity of the man is approximately 0.588 m/s forward
