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An ambulance is traveling north at 56.7 m/s, approaching a car that is also traveling north at 36.4 m/s. The ambulance driver hears his siren at a frequency of 726 Hz. Ambulance 56.7 m/s 36.4 m/s Car What is the wavelength at any position in front of the ambulance for the sound from the ambulance’s siren? The velocity of sound in air is 343 m/s. Answer in units of m. 002 (part 2 of 2) 10.0 points At what frequency does the driver of the car hear the ambulance’s siren? Answer in units of Hz.

Respuesta :

Answer:

Explanation:

At any position in front of the ambulance , it is source of sound which is moving at 56.7 m/s having frequency of n₀ = 726

Apparent frequency = n₀ x V /( V - Vs ) , V is velocity of sound , Vs is velocity of source

= 726 x 343 / (343 - 56.7)

= 869.77 Hz

wave length = velocity of sound / apparent frequency

=  343 / 869.77

= .394 m

b )

For observer in the car

apparent frequency

= n₀ x [(V- V₀ ) /( V - Vs )] , V₀ is velocity of observer or car

= 726 x  [(343- 36.4 ) /( 343 - 56.7 )]

= 726 x 306.6 / 286.3

= 777.47 Hz .

Lanuel

1. The wavelength at any position in front of the ambulance for the sound from the ambulance’s siren is 0.394 meter.

2. The frequency at which the driver (observer) of the car hear the ambulance’s siren is equal to 962.10 Hertz.

Given the following data:

  • Observer velocity = 36.4 m/s
  • Frequency of sound = 726 Hz
  • Source velocity = 56.7 m/s
  • Velocity of sound = 343 m/s

1. To determine the wavelength at any position in front of the ambulance for the sound from the ambulance’s siren, we would apply Doppler's effect of sound waves:

Mathematically, Doppler's effect of sound waves is given by the formula:

[tex]F_o = \frac{FV }{V\; - \;V_s}[/tex]

Where:

  • [tex]F_a[/tex] is the apparent frequency.
  • V is the speed of a sound wave.
  • F is the actual frequency of sound.
  • [tex]V_s[/tex] is the source velocity.

Substituting the given parameters into the formula, we have;

[tex]F_a = \frac{726 \times 343 }{343\; - \;56.7}\\\\F_a = \frac{249018 }{286.3}\\\\F_a = 869.78\;Hz[/tex]

For wavelength:

[tex]Wavelength=\frac{Velocity}{Apparent\;frequency} \\\\Wavelength=\frac{343}{869.78}[/tex]

Wavelength = 0.394 meter.

2. To determine the frequency at which the driver (observer) of the car hear the ambulance’s siren:

[tex]F_o = \frac{V \;+ \;V_o}{V\; - \;V_s} F\\\\F_o = \frac{343 \;+ \;36.4}{343\; - \;56.7} \times 726\\\\F_o = \frac{379.4}{286.3} \times 726\\\\F_o = 1.3252 \times 726\\\\F_o =962.10 \;Hz[/tex]

Read more on frequency here: https://brainly.com/question/23460034

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