Respuesta :
Answer:
5
Step-by-step explanation:
Use the distance formula [tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
insert the numbers into the formula [tex]d=\sqrt{(2+1)^2+(0-4)^2}[/tex]
2+1=3 and 0-4=-4
[tex]3^2[/tex] =9 and [tex]-4^{2}[/tex] = 1
9+16=25
the square root of 25 is 5
Answer:
The distance would be 5
Step-by-step explanation:
You would have to use the distance formula, which is:
[tex]d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}[/tex]
The coordinate 2 is [tex]x_{2}[/tex] and coordinate -1 is [tex]x_{1}[/tex]
And the coordinate 0 is [tex]y_{2}[/tex] and 4 is [tex]y_{1}[/tex]
So now we would put those values into the formula as follows:
[tex]d=\sqrt{((2)-(-1))^{2}+((0)-(4))^{2} }[/tex]
According to PEMDAS, we would have to evaluate parenthesis first
*Keep in mind that two negative signs equal a positive
[tex]d= \sqrt{(3)^{2}-(4)^{2}}[/tex]
Following with PEMDAS, we'll now square both numbers
[tex]d=\sqrt{9+16}[/tex]
Evaluate
[tex]d=\sqrt{25}[/tex]
And simplify
[tex]d= 5[/tex]
