Answer:
[tex]\tau=3.48*10^{-26}Nm[/tex]
Explanation:
The torque equation is given by:
[tex]\tau=IABsin(\theta)[/tex]
Where:
So:
[tex]\tau=1.05*10^{4}*\pi *(0.65*10^{-15})^{2}*2.5[/tex]
Therefore the torque is:
[tex]\tau=3.48*10^{-26}Nm[/tex]
I hope it helps you!
Answer:
The maximum torque on a proton in a 2.50 T field is 1.39 × 10⁻²⁵ N.m
Explanation:
The equation for torque in circular current loop as a result of the magnetic force is given by:
T = IABsin(Θ)
Where:
T is the torque
I is the current in the loop
A is the surface area of the circular current loop
B is the magnetic field intensity
Θ is the angle between the loop plane and the direction of the magnetic field.
Given that:
I = 1.05 × 10⁴ A
the radius r = 0.65 × 10⁻¹⁵ m
A = 4πr² = 4 × π × (0.65 × 10⁻¹⁵)² = 5.308 × 10⁻³⁰ m²
B = 2.50 T
The torque is maximum at Θ = 90°
Since T = IABsin(Θ)
substituting values
T = 1.05 × 10⁴ × 5.308 × 10⁻³⁰ × 2.5 × sin(90)
T = 1.39 × 10⁻²⁵ N.m
The maximum torque on a proton in a 2.50 T field is 1.39 × 10⁻²⁵ N.m
