The length of a rectangle is 10 inches longer than the width. The perimeter is 56 inches. Find the length and the width of the rectangle

Respuesta :

Answer:

[tex]Length=19\,inches\\\\Width=9\,inches[/tex]

Step-by-step explanation:

Let, the length of the rectangle be 'L',

Width of the rectangle be 'W'

[tex]L=(W+10)\,inches[/tex]

Perimeter of the rectangle= [tex]56\,inches[/tex]

Perimeter of the rectangle= [tex]2(Length+Width)[/tex]

                     [tex]56=2(W+10+W)\\\\\dfrac{56}{2} =W+10+W\\\\28=2W+10\\\\28-10=2W\\\\18=2W\\\\W=\dfrac{18}{2}\\\\ W=9\,inches[/tex]

As,

     [tex]L=(W+10)\,inches[/tex]

     [tex]L=9+10\\\\L=19\,inches[/tex]

[tex]Length=19\,inches\\\\Width=9\,inches[/tex]