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What is the equation of the line that is parallel to the line y - 1 = 4(x + 3) and passes through the point (4, 32)?
y=-1x +33
y=-3x + 36
y = 4x - 16
y = 4x + 16

Respuesta :

amna04352

Answer:

y = 4x + 16

Step-by-step explanation:

y - 1 = 4(x + 3)

Has a slope of 4

y = 4x + c

32 = 4(4) + c

32 - 16 = c

c = 16

y = 4x + 16
The answer is letter D
y=4x+16