Answer:
A) 0.125 m (the image is real)
B) -0.4 m (the image is virtual)
Explanation:
For both situations we will use the Lens Equation:
[tex]\frac{1}{f}=\frac{1}{v}+\frac{1}{u}[/tex] (1)
Where:
[tex]f=0.1 m[/tex] is the focal length
[tex]u[/tex] is the distance between the object and the lens
[tex]v[/tex] is the distance between the image and the lens
Isolating [tex]v[/tex]:
[tex]v=\frac{uf}{u-f}}[/tex] (2)
Knowing this, let's begin with the answers:
A) When [tex]u=0.5 m[/tex]
[tex]v=\frac{(0.5 m)(0.1 m)}{0.5 m-0.1 m}}[/tex]
[tex]v=0.125 m[/tex] The image is real
B) When [tex]u=0.08 m[/tex]
[tex]v=\frac{(0.08 m)(0.1 m)}{0.08 m-0.1 m}}[/tex]
[tex]v=-0.4 m[/tex] The negative sign indicates the image is virtual
