Lin and Jada each walk at a steady rate from school to the library. Lin can walk 13 miles in 5 hours, and Jada can walk 25 miles in 10 hours. They each leave school at 3:00 and walk 3 and 1/4 miles to the library. What time do they each arrive?

Respuesta :

Answer:

Step-by-step explanation:

Given parameters:

Rate of walking by Lin = 13 miles in 5 hours

Rate of walking by Jada  = 25 miles in 10 hours

Distance walked = 3.25 miles

Time of take off = 3:00

Solution:

The rate of their walking amounts to their speed;

             Speed  = [tex]\frac{distance}{time}[/tex]

Speed of Lin  = [tex]\frac{13}{5}[/tex]   = 2.6 miles/hr

Speed of Jada = [tex]\frac{25}{10}[/tex]  = 2.5 miles/hr

To find the time; make it the subject of formula and solve for each person;

                       Time  = [tex]\frac{distance}{speed}[/tex]

 Time of Lin  = [tex]\frac{3.25}{2.6}[/tex]  = 1.25hr    = 48 minutes

  Time of Jada  = [tex]\frac{3.25}{2.5}[/tex]   =  1.3hr   = 47 minutes

Time for each to arrive;

              Lin  = 3.00 +  1.25hr  = 4:25

              Jada  = 3.00 +  1.30hr    = 4:30