Step-by-step explanation:
A dice has 6 outcomes, S = [1, 2, 3, 4, 5, 6}
When two dice are rolled, the no of outcomes n (S) = 6 * 6 = 36
S = { (1, 1), (1, 2)..... (1, 6)
(2, 1).............(2, 6)
..................... (6,6) }
Le X be the event that sum of two dice when rolled is at most 5
At most refers to lesser than or equal to,
Therefore the outcomes for event X = { (1, 1) , (1, 2) , (1, 3) , (1, 4) , (2, 1) , (2, 2) , (2, 3) , (3, 1) , (3, 2) , (4 , 1) }
n (X) = 10
P (X) = n (X) / n (S)
= 10 / 36 = 5 / 18
