Answer:
Relation between initial speed of bullet and height h is given as
[tex]v = \frac{m + M}{m}\sqrt{2gh}[/tex]
Explanation:
As we know that system of block and bullet swings up to height h after collision
So we have
[tex](m + M)gh = \frac{1}{2}(m + M)v_1^2[/tex]
so we have
[tex]v_1 = \sqrt{2gh}[/tex]
so speed of the block + bullet just after the impact is given by above equation
Now we also know that there is no force on the system of bullet + block in the direction of motion
So we can use momentum conservation
[tex]mv = (m + M)v_1[/tex]
now we have
[tex]v = \frac{m + M}{m}\sqrt{2gh}[/tex]