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A car carrying a 71 kg test dummy crashed into a wall at 24m/s and is brought to rest in .10s. What is the magnitude of the average force exerted by the seat belt on the dummy

Respuesta :

The answer for the following problem is mentioned below.

  • Therefore the force exerted by the seat belt on the dummy is 170.4 N  

Explanation:

Given:

mass of the dummy (m) = 71 kg

velocity of the dummy (v) = 24 m/s

time (t) = 10 seconds

To solve:

Average force exerted (F)

We know;

To calculate the average force;

According to the formula;

F = (m × v) ÷ t

Where;

F represents the force exerted

m represents the mass of the dummy

v represents the velocity

t represents the time

F = [tex]\frac{m*v}{t}[/tex]

F = [tex]\frac{71*24}{10}[/tex]

F = [tex]\frac{1704}{10}[/tex]

F = 170.4 N

Therefore the force exerted by the seat belt on the dummy is 170.4 N  

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