Answer: 310K
Explanation:
Given that:
Volume of Chlorine gas V = 10.2L
Temperature T = ?
Pressure P = 1.83 atm
Number of moles of chlorine gas N = 0.734 moles
Molar gas constant R is a constant with a value of 0.0821 atm L K-1 mol-1
Then, apply ideal gas equation
pV = nRT
1.83atm x 10.2L= 0.734 moles x 0.0821 atm L K-1 mol-1 x T
18.67atm L = 0.0603 atm L K-1 x T
T = (18.67atm L / 0.0603 atm L K-1)
T = 309.8K (Round up to 310K)
Thus, the temperature of the chlorine gas is 310 kelvin
