Answer:
[tex]0.0112 \Omega[/tex]
Explanation:
The resistance of an object tells us how much the object opposes to the flow of current through it.
The resistance of a conductor is given by the formula
[tex]R=\frac{\rho L}{A}[/tex]
where
[tex]\rho[/tex] is the resistivity of the material
L is the length of the conductor
A is the cross-sectional area
For the tungsten rod in this problem, we have:
L = 20.0 m is the length
[tex]A=1.00\cdot 10^{-4}m^2[/tex] is the cross-sectional area
[tex]\rho=5.6\cdot 10^{-8} \Omega \cdot m[/tex] is the resistivity of tungsten at 20C
Substituting into the formula, we find the resistance of the tungsten rod:
[tex]R=\frac{(5.6\cdot 10^{-8})(20.0)}{1.00\cdot 10^{-4}}=0.0112 \Omega[/tex]
