Answer:
T₂ = 101.13 K OR
- 172.02 °C
Explanation:
Given data:
Initial pressure of gas = 755 Kpa
Initial temperature = 30.0°C
Final temperature = ?
Final pressure = 252 Kpa
Solution;
Initial temperature = 30.0°C (30+273 = 303 K)
According to Gay-Lussac Law,
The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.
Mathematical relationship:
P₁/T₁ = P₂/T₂
Now we will put the values in formula:
755 Kpa / 303 K = 252 Kpa / T₂
T₂ = 252 Kpa ×303 K / 755 Kpa
T₂ = 76356 KPa.K / 755 Kpa
T₂ = 101.13 K
Kelvin to °C:
101.13 K - 273.15 = - 172.02 °C
