Answer:
[tex]176\pi in.^3[/tex]
Step-by-step explanation:
The figure of the problem is missing: find it in attachment.
In this problem, the container has a shape of a cylinder.
The volume of a cylinder is given by the formula:
[tex]V=\pi r^2 h[/tex]
where
V is the volume
r is the radius of the base of the cylinder
h is its height
For the container in this problem, we have:
r = 4 in. is the radius of the base
h = 11 in. is the height of the container
Substituting into the formula, we can find the volume of the container, and so the volume of grain that it can contain:
[tex]V=\pi (4)^2 (11)=176\pi in.^3[/tex]
To solve such problems we need to know about Volume.
Volume is the quantity that helps us to know the holding capacity of a container or closed surface. It is given by the formula,
Volume of a cylinder = [tex]\bold{\pi \times (radius)^2 \times Height}[/tex],
The volume of the grain that the container can hold is 44π in.³.
Given to us,
The radius of the cylinder, r = [tex]\bold{\dfrac{Diameter}{2} = \dfrac{4}{2} = 2\ in.}[/tex]
Substituting the values for the cylinder,
Volume of the grain container can hold = [tex]\bold{\pi \times (radius)^2 \times Height}[/tex]
= π x 2² x 11
= π x 4 x 11
= 44π in.³
Hence, the volume of the grain that the container can hold is 44π in.³.
Learn more about Volume of a cylinder:
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