Answer:
3.527 seconds
Explanation:
The height of the falling water, assuming no friction or air resistance, is given by ...
h(t) = -(1/2)gt² +61
where g is the standard gravity value, 9.80665 m/s².
The the time required for h(t) = 0 is ...
1/2gt² = 61
t² = 2·61/g
t = √(2·61/9.80665) ≈ 3.527 . . . . seconds