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Consider the solubilities of a particular solute at two different temperatures. Temperature ( ∘ C ) Solubility ( g / 100 g H 2 O ) 20.0 32.2 30.0 70.2 Suppose a saturated solution of this solute was made using 56.0 g H 2 O at 20.0 °C. How much more solute can be added if the temperature is increased to 30.0 ∘ C? mass:

Respuesta :

Answer:

21.28 grams solute can be added if the temperature is increased to 30.0°C.

Explanation:

Solubility of solute at 20°C = 32.2 g/100 grams of water

Solute soluble in 1 gram of water = [tex]\frac{32.2}{100}g=0.322 g[/tex]

Mass of solute in soluble in 56.0 grams of water:

[tex]0.322\times 56.0=18.032 g[/tex]

Solubility of solute at 30°C = 70.2g/100 grams of water

Solute soluble in 1 gram of water = [tex]\frac{70.2}{100}g=0.702 g[/tex]

Mass of solute in soluble in 56.0 grams of water:

[tex]0.702 \times 56.0=39.312 g[/tex]

If the temperature of saturated solution of this solute using 56.0 g of water at 20.0 °C raised to 30.0°C

Mass of solute in soluble in 56.0 grams of water 20.0°C = 18.032 g

Mass of solute in soluble in 56.0 grams of water at 30.0°C = 39.312 g

Mass of of solute added If the temperature of the saturated solution increased to 30.0°C:

39.312 g - 18.032 g = 21.28 g

21.28 grams solute can be added if the temperature is increased to 30.0°C.