Answer:
[tex]H_{rxn} = -93.52 \frac{KJ}{mol}[/tex]
The final temperature [tex]T_{2} = 50.21[/tex] ° c
Explanation:
(a).
[tex]H_{rxn} = H_{products} - H_{reactents}[/tex]
[tex]H_{reactants}[/tex] = - 813.9 [tex]\frac{KJ}{mol}[/tex]
[tex]H_{Products}[/tex] = - 907.51 [tex]\frac{KJ}{mol}[/tex]
[tex]H_{rxn} = -907.51 + 813.9[/tex]
[tex]H_{rxn} = -93.52 \frac{KJ}{mol}[/tex]
(b).
[tex]H_{rxn} = -93.52 \frac{KJ}{mol}[/tex]
E = 93520 J
C = 3.5 [tex]\frac{KJ}{kg K}[/tex]
Initial temperature [tex]T_{1} = 25[/tex] ° c
Mass (m) = density × volume
m = 1060 × 1
m = 1060 gm
[tex]E = m C (T_{2} - T_{1} )[/tex]
93520 =1060 × 3.5 × ( [tex]T_{2}[/tex] - 298 )
[tex]T_{2} = 50.21[/tex] ° c
This is the final temperature.
(c).
The density of sulfuric acid is more than the water. so when water is added to acid the mixing process does not takes properly. So we have to add acid in to the water.
Adding water is exothermic process so when we add water to acid than in that case more energy produces and wasted.