Respuesta :
Answer:
1498502.2 m/s
Explanation:
mass of the helium = 6.68×10−27kg
energy released during the decay = 1.5×10−14J
since all the energy released is converted to kinetic energy of the alpha particle then particle will have kinetic energy = 0.5 mh v²
1.5×10−14J = 2 ( 0.5 mh v²) where mh is mass of helium
1.5×10−14J / ( 6.68×10−27kg) = v²
v = 1498502.2 m/s
Answer:
v = 1498502.2 m/s
Explanation:
All energy that was released is been converted to kinetic energy of the alpha particle, particle having a kinetic energy of = 0.5 mh v²
We are given the following as;
mass of the helium = 6.68×10−27kg
decay process release energy of = 1.5×10−14J
Calculating the speed of alpha particle after the release in this equation, we have
1.5×10−14J = 2 ( 0.5 mh v²)
Substituting the value of mh in the equation, we have
v² = 1.5×10−14J / ( 6.68×10−27kg)
To eliminate the square root, we introduce square root to both sides
√v² = √1.5×10−14J / ( 6.68×10−27kg)
v= 1498502.2 m/s
