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y- 8x-2 and y Rajib wrote the equations5. What can Rajib conclude about the solution to this system ofequations?o The point (2,14) is a solution to of equationsthis system o The point (14, 2) is a solution to this system of equationso The point -4s a solution to this system of equationso The point4-4 is a solution to this system of equations.

y 8x2 and y Rajib wrote the equations5 What can Rajib conclude about the solution to this system ofequationso The point 214 is a solution to of equationsthis sy class=

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texaschic101
its just a matter of subbing in ur answer choices to see which ones are correct...but remember, for it to be a solution, it has to satisfy BOTH equations.

(-1/4,-4)
y = 8x - 2
-4 = 8(-1/4) - 2
-4 = - 8/4 - 2
-4 = -2-2
-4 = -4 (correct)

(-1/4,-4)
y = -4x - 5
-4 = -4(-1/4) - 5
-4 = 1 - 4
-4 = -4 (correct)

Therefore, ur solution is (-1/4,-4)

Answer with explanation:

The two linear equation which are in two variables are

   y = 8 x -2---------(1)

  y = -4 x -5----------(2)

Equating ,(1) and (2)

→ 8 x -2 = -4 x -5

→8 x + 4 x= 2 -5

→12 x = -3

[tex]x=\frac{-3}{12}\\\\x=\frac{-1}{4}[/tex]

Substituting the value of , x in equation 1

[tex]y=8 \times \frac{-1}{4} -2\\\\y=-2-2\\\\y=-4[/tex]

So, the point of intersection of two lines are

     [tex](\frac{-1}{4}, -4)[/tex]

Option D

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