Respuesta :
There are 5 x 10 = 50 different outcomes.
Of them only 3x10, 4x10, 4x9, 4x8, 5x10, 5x9, 5x8, 5x7 and 5x6 are greater or equal than 30. Those are 9 possibilities.
Then 50 - 9 = 41 are the possibilities that the product of the two numbers is less than 30.
The probalility, then, is 41/50 = 0.82
Of them only 3x10, 4x10, 4x9, 4x8, 5x10, 5x9, 5x8, 5x7 and 5x6 are greater or equal than 30. Those are 9 possibilities.
Then 50 - 9 = 41 are the possibilities that the product of the two numbers is less than 30.
The probalility, then, is 41/50 = 0.82
Answer: [tex]\dfrac{41}{50}[/tex]
Step-by-step explanation:
Given : The number of sections in Paco's spinner =5
The number of sections in Manu's spinner =10
Now, if both spin together , the total number of possible outcomes :-
[tex]5\times10=50[/tex]
The outcomes when the product is more than 30 :-
(5,6), (5,7), (5,8), (5,9), (5, 10), (4,8), (4,9), (4, 10), (3,10)
The number of favorable outcomes for the product of Manu's number and Paco's number is less than 30 :-
[tex]50-9=41[/tex]
Now, the probability that the product of Manu's number and Paco's number is less than 30 :-
[tex]=\dfrac{41}{50}[/tex]
Hence, the probability that the product of Manu's number and Paco's number is less than 30 [tex]=\dfrac{41}{50}[/tex].