Calculate the enthalpy for the following reaction. During the reaction, the temperature changes from 42.5 C to 37 C. The specific heat of HCl is 4.04J/g*C. Is the reaction endothermic or exothermic?

Respuesta :

Answer:

[tex]q = 0.810[/tex] Kj/mol

Its an endothermic reaction

Explanation:

Enthalpy can be evaluated by using following formula -

[tex]q = m * c* \delta T[/tex]

where

q is the enthalpy or change in internal energy

m is the mass in kg

c is the specific heat

and [tex]\delta T[/tex] is the change in temperature

Mass of HCl is equal to [tex]36.46[/tex] g/mol

or

Mass of HCl is equal to [tex]0.03646[/tex]  Kg/mol

Substituting the given values in above equation, we get-

[tex]q = 0.03646 * 4.04 * (42.5 - 37)\\q = 0.03646 * 4.04 * 5.5 \\[/tex]

[tex]q = 0.810[/tex] Kj/mol

Enthalpy is positive thus it is an endothermic reaction