How many grams of carbon
tetrafluoride, CF4, are produced
from the complete reaction of 1.46
moles of carbon?

Respuesta :

Answer:

128g

Explanation:

[tex]n(CF4)=n(C)=1.46molM(CF4)=(1×12+4×19)gmol−1=88gmol−1m(CF4)=nM=1.46mol×88gmol−1=128g (3s.f[/tex]

Answer:

128 grams

Explanation: