Respuesta :

Answer:

[tex]6c - 5 = \frac{c(3d - 4y)}{8d} \\ 8d(6c - 5) = c(3d - 4y) \\ 48dc - 40d = 3cd - 4cy \\ - 40 = 3cd - 4cy - 48dc \\ - 40 d = c(3d - 4y - 48d) \\ c = \frac{ - 40d}{3d - 4y - 48d} [/tex]

Answer:

  [tex]c=\dfrac{40d}{45d+4y}\\\\c=\dfrac{16}{15}[/tex]

Step-by-step explanation:

a) Solve for c in the same way you might if all the other variables were numbers.

  [tex]6c-5=\dfrac{c(3d-4y)}{8d}\\\\8d(6c-5)=c(3d-4y)\\\\48cd-40d-c(3d-4y)=0\\\\c(48d-3d+4y)=40d\\\\\boxed{c=\dfrac{40d}{45d+4y}}[/tex]

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b) Filling in the given numbers, we have ...

  c = 40(8/5)/(45(8/5) +4(-3)) = 64/(72-12) = 64/60

  c = 16/15