Answer:
The set solution is [1,4]
Step-by-step explanation:
To find the solution set
Expand,
(x - 2)(x - 3) =
Now, x² - 5x + 6 = 2
we want the right to be = 0 so subtract 2 from both sides
x² - 5x + 6 - 2 = 2 - 2
x² - 5x + 4 = 0
we can now use the quadratic formula,
[tex]x = \frac{-(-5)+\sqrt{(-5)^{2}-4*1*4 } }{2*1}[/tex]
[tex]x = \frac{(5)+\sqrt{(25)-4*4 } }{2}[/tex][tex]= \frac{(5)+\sqrt{(25)-16 } }{2}[/tex][tex]= \frac{(5)+\sqrt{9} }{2}[/tex]
[tex]x = \frac{(5)+3 }{2}[/tex] = 4
[tex]x = \frac{(5)-3 }{2} \\[/tex] = 1
Hence the set solution is [1,4]
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