Respuesta :
Answer:
ph =-log (28 x 10^-2)
= -(log 28 +log10^-2) ie using indices
= -(1.44+(-2) )
=-(-0.56)
= 0.56
=approximately (1) ans
Answer:
ph =-log (28 x 10^-2)
= -(log 28 +log10^-2) ie using indices
= -(1.44+(-2) )
=-(-0.56)
= 0.56
=approximately (1) ans