habiba2003hisham
contestada

Calculate the intensity of the sound waves from an electric guitar’s amplifier at a
distance of 5.0 m when its power output is equal to each of the following values:
a. 0.25 W
b. 0.50 W
c. 2.0 W

Respuesta :

oladayoademosu

Answer:

a. 0.8 mW/m² b. 1.6 mW/m² c. 6.4 mW/m²

Explanation:

Intensity,I = P/A were P = power and A = area = 4πr² were r = distance from electric guitar = 5.0 m.

a. When P = 0.25 W, I = 0.25 W/4π5² = 0.25 W/100π = 0.00079 W/m² ≅ 0.0008 W/m² =  0.8 mW/m²

b. When P = 0.50 W, I = 0.50 W/4π5² = 0.50 W/100π = 0.00156 W/m² ≅ 0.0016 W/m² =  1.6 mW/m²

c. When P = 2.0 W, I = 2.0 W/4π5² = 2.0 W/100π = 0.00636 W/m² ≅ 0.0064 W/m² =  6.4 mW/m²

okpalawalter8

Answer:

  • The intensity for power at 0.25W = [tex]7.957*10^{-4}W/m^2[/tex]
  • The intensity for power at 0.5W = [tex]1.5915*10^{-3}W/m^2[/tex]
  • The intensity for power at 2W = [tex]6.366*10^{-3}W/m^2[/tex]

Explanation:

A) When power output P = 0.25W

Intensity of the sound wave,

[tex]I = \frac{P}{4\pir^2} \\\\ I = \frac{0.25}{4\pi*5^2}\\\\I = 7.957*10^{−4}W/m^2[/tex]

B) When P = 0.5W

Intensity of the sound wave,

[tex]I = \frac{P}{4\pir^2} \\\\ I = \frac{0.5}{4\pi*5^2}\\\\I = 1.5915*10^{-3}W/m^2[/tex]

C) When P = 2W

Intensity of the sound wave,

[tex]I = \frac{P}{4\pir^2} \\\\ I = \frac{2}{4\pi*5^2}\\\\I = 6.366*10^{-3}W/m^2[/tex]

For more information, visit

https://brainly.com/question/16152533

Otras preguntas