Answer:
The new force between the charges becomes double of the initial force.
Explanation:
The force acting between charge particles is given by :
[tex]F=k\dfrac{q_1q_2}{r^2}[/tex]
k is electrostatic constant
r is distance between charges
If one of the charges are doubled, then, q₁ = 2q₁
The new force becomes,
[tex]F'=\dfrac{2kq_1q_2}{r^2}\\\\F'=2F[/tex]
So, the new force between the charges becomes double of the initial force.
