PLZZ HELP

Graph the function f(x)=x^2-4x-12 on the coordinate plane.

A)What are the x-intercepts
B)What is the y-intercept?
C)What is the vertex?

Respuesta :

Answer:

A) (-2,0) and (6,0)

B) (0,-12)

C) (2,-16)

Step-by-step explanation:

In the graph you see below, you can tell that the two x intercepts are at (-2,0) and (6,0), while the y intercept is at (0,-12). You can also see that the vertex is at (2,-16). Hope this helps!

Ver imagen osikbro

The x intercept will be ( -2,0 ) and ( 6,0 ) , y intercept will be ( 0, -12 ) and vertex will be at ( 2 , -16 ).

What is a function?

A certain kind of relationship called a function binds inputs to essentially one output.

The machine will only accept specified inputs, described as the function's domain, and will potentially produce one output for each input.

Given the function,

f(x)=x²-4x-12

A) x-intercept;

For the x-intercept, the value of y or f(x) will be 0 so.

0 = x² -4x -12 ⇒ x = -2 , 6

So

x-intercept will be ( -2,0 ) and ( 6,0 ).

B) y-intercept

At the y-intercept the value of x will be 0 so

f(x) = -12

So

The y-intercept will be ( 0, -12 ).

C) Vertex

For vertex the slope will be 0 so

f'(x) = 0 ⇒ 2x - 4 = 0 ⇒ x = 2

The value of y at x = 2 will be

f(2) = -16

so

vertex will be at ( 2, -16 ).

For more about the function

brainly.com/question/23712366

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