Answer:
[tex] \boxed{p = 4} [/tex]
Step-by-step explanation:
[tex] = > {p}^{2} = 16 \\ \\ = > {p}^{ \cancel{2}} = {4}^{ \cancel{2}} \\ \\ = > p = 4 \\ \\ \\ OR \\ \\ \\ = > {p}^{2} = 16 \\ \\ = > {p}^{2} = {4}^{2} \\ \\ = > p = \sqrt{ {4}^{2} } \\ \\ = > p = {4}^{ \cancel{2} \times \frac{1}{ \cancel{2}} } \\ \\ = > p = 4 [/tex]
Using the given equation, we know that the square root of p = 16.
Because of this, we also know that the square root of 16 will equal p.
[tex]\sqrt{16} = 4[/tex]
Therefore, p is equal to 4, or p = [tex]\sqrt{16}[/tex].
Hope this helped! :)
