Answer:
[tex]P(X=2) =0.3906[/tex]
Step-by-step explanation:
Proportion of students using the app, p = 63/100 = 0.63
Proportion of students not using the app, q = 1 - 0.63 = 0.37
Sample size, n = 2
Probability that the two students are using the app.
[tex]P(X = r) = nCr p^{n} q^{n-r} \\P(X = 2) = 2C2 *0.63^{2} *0.37^{2-2}\\P(X = 2) = 2C2 *0.63^{2} *0.37^{0}\\P(X=2) = 0.63^{2} \\P(X=2) =0.3906[/tex]
