Respuesta :
Hello,
Method 1:
z=f(x,y)=4x²+5xy-y²-6=0
z'=8x+5y+5xy'-2yy'=0
y'(5x-2y)=-(8x+5y)
y'=-(8x+5y)/(5x-2y)
Method 2:
@f/@x=8x+5y
@f/@y=5x-2y
dy/dx=-(@f/@x)/(@f/@y)=-(8x+5y)/(5x-2y)
Method 1:
z=f(x,y)=4x²+5xy-y²-6=0
z'=8x+5y+5xy'-2yy'=0
y'(5x-2y)=-(8x+5y)
y'=-(8x+5y)/(5x-2y)
Method 2:
@f/@x=8x+5y
@f/@y=5x-2y
dy/dx=-(@f/@x)/(@f/@y)=-(8x+5y)/(5x-2y)
So the question ask to find dy/dx by implicit differentiation of 4x^2 + 5xy - y2=6, and base on my further calculation and further computation about the said question, I would say that the answer would be dy/dx = (8x+5y)/(2y-5x). I hope you are satisfied with my answer and feel free to ask for more