Math Questions!


07.02 LC)

Alicia rolls two fair number cubes numbered from 1 to 6. She first defines the sample space, as shown below:

(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)
(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)
(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)
(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)

Based on the sample space, what is the probability of getting a total of 7?

4 over 36

5 over 36

6 over 36

8 over 36





(07.01 MC)

The number of chips of different colors in Gail's bag is shown below:
•3 blue chips
•4 pink chips
•8 white chips

Gail takes out a chip from the bag randomly without looking. She replaces the chip and then takes out another chip from the bag. What is the probability that Gail takes out a white chip in both draws?

8 over 15 multiplied by 7 over 14 is equal to 56 over 210

8 over 15 plus 7 over 14 is equal to 217 over 210

8 over 15 plus 8 over 15 is equal to 16 over 15

8 over 15 multiplied by 8 over 15 is equal to 64 over 225





Sue used a probability simulator to roll a 6-sided number cube and flip a coin 100 times. The results are shown in the tables below:



Number on cube vs Number of times rolled

1 18
2 25
3 12
4 32
5 3
6 10


Heads = 56

Tails = 44




Using Sue's simulation, what is the probability of rolling a 2 on the number cube and the coin landing heads up?

81 over 100

56 over 100

1400 over 10000

1100 over 10000

Respuesta :

[tex]Q1.\\\Omega=\{(x;\ y)|\ x,\ y\in\{1;\ 2;\ 3;\ 4;\ 5;\ ;6\}\}\\\\\overline{\overline{\Omega}}=6\cdot6=36\\\\A=\{(1;\ 6);\ (2;\ 5);\ (3;\ 4);\ (4;\ 3);\ (5;\ 2);\ (6;\ 1)\}\\\\\overline{\overline{A}}=6\\\\P(A)=\dfrac{\overline{\overline{A}}}{\overline{\overline{\Omega}}}\Rightarrow P(A)=\dfrac{6}{36}\leftarrow Answer[/tex]


[tex]Q2.\\3+4+8=15-number\ of\ all\ chips\\\\8\ white\ chips\\\\P(B)=\dfrac{8}{15}\cdot\dfrac{8}{15}=\dfrac{64}{225}\leftarrow Answer[/tex]


[tex]Q3.\\25-number\ of\ 2\\56-number\ of\ heat\\100-number\ of\ all\\\\\dfrac{25}{100}\cdot\dfrac{56}{100}=\dfrac{1400}{10000}\leftarrow Answer[/tex]
[tex]Question \ 1)[/tex] 

[tex] Two \ numbers \ written \ in \ a \ certain \ order \ are \ known \ as [/tex]
[tex]ordered \ pairs.[/tex] 

[tex]Ordered \ pair \ that \ add \ up \ to \ 7 \ (6,1) (5,2) (4,3) (3,4) (2,5) (1,6)[/tex]

[tex]P(A)= \dfrac{6}{36} [/tex] 

[tex]Question \ 2) [/tex] [tex]3+4+8=15 \ Total \ number \ of \ chips [/tex]

[tex]Where \ 8 \ represents \ = white[/tex] 

[tex]P(B)= \dfrac{8}{15}* \dfrac{8}{15} = \dfrac{64}{225} = Solution[/tex] 

[tex]Question \ 3) [/tex]

[tex]Convert \ to \ fraction \ and \ muliply[/tex]

[tex]The \ numerator \ in \ a \ fraction \ represents \ the \ number \ of \ pieces \ [/tex] 
[tex]selected.[/tex][tex] If \ the \numerator \ is \ larger \ than \ the \ denominator, the \ number \ is \ larger \ [/tex][tex]than \ one.[/tex]

[tex]The \ denominator \ in \ a \ fraction \ represents \ the \ total \ number \ [/tex]
[tex]of \ equal \ size \ pieces \ that \ make \ up \ a \ whole. [/tex]

[tex] \dfrac{25}{100} * \dfrac{56}{100}= \dfrac{1400}{10000} [/tex]