Answer:
Δτ = 50 N.m
Explanation:
The torque applied on an object is given by the product of the force applied on it and the perpendicular distance between the force and the axis of rotation of the object. That is:
τ = F r
where,
τ = Torque applied on the object
F = Force applied on it
r = distance from axis of rotation
FOR HANDLE SIDE OF DOOR:
τ₁ = F r₁
where,
τ₁ = Torque applied on the object = ?
F = Force applied on it = 100 N
r₁ = distance from axis of rotation = 1 m
Therefore,
τ₁ = (100 N)(1 m)
τ₁ = 100 N.m
FOR MIDDLE OF DOOR:
τ₂ = F r₂
where,
τ₂ = Torque applied on the object = ?
F = Force applied on it = 100 N
r₂ = distance from axis of rotation = 1 m/2 = 0.5 m
Therefore,
τ₂ = (100 N)(0.5 m)
τ₂ = 50 N.m
Now, the difference between the amount of torque in both cases is:
Δτ = τ₁ - τ₂
Δτ = 100 N.m - 50 N.m
Δτ = 50 N.m
