Complete Question
The
Answer:
a
[tex]E_r = 3.058 \ J[/tex]
b
[tex]E_b = -11.466 \ J[/tex]
c
[tex]\Delta E_n = -14.524 \ J[/tex]
Explanation:
From the question we are told that
The mass of the stone is [tex]m_s = 0.26 \ kg[/tex]
The height above the top of the water is [tex]h = 1.2 \ m[/tex]
The depth of the well is [tex]d = 4.5 \ m[/tex]
The gravitational potential of the stone before it was released is
[tex]E_r = mgh[/tex]
substituting values
[tex]E_r = 0.26 * 9.8 * 1.2[/tex]
[tex]E_r = 3.058 \ J[/tex]
The gravitation potential of the stone when it reaches the bottom of the well is
[tex]E_b = mg(- d)[/tex]
The negative shows that the potential energy of the stone as compared to the earth is reducing
substituting values
[tex]E_b = 0.26 * 9.8 *(- 4.5)[/tex]
[tex]E_b = -11.466 \ J[/tex]
The change in the systems gravitational potential is
[tex]\Delta E_n = E_b - E_r[/tex]
substituting values
[tex]\Delta E_n = -11.466 - 3.058[/tex]
[tex]\Delta E_n = -14.524 \ J[/tex]
