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A gas sample that has a pressure of 4.23 atm, a volume of 1,870 mL, and a temperature of 293 K is allowed to expand to a volume of 6.01 L with a final temperature of 373 K. What is the final pressure of the gas in atmospheres?

Respuesta :

jamesesther1234

Answer:

1.68 atm.

Explanation:

Given:

P1 = 4.23atm

V1 = 1870 mL

T1 = 293K

P2 = ?

V2 = 6.01 L = 6010 mL

T2 = 373 K

Assuming number of moles and R is constant:

[tex]\frac{P1V1}{T1} = \frac{P2V2}{T2}[/tex]

⇒ P2 = [tex]\frac{P1V1T2}{T1V2}[/tex] = [tex]\frac{2,950,467.3}{1,760,930}[/tex]

= 1.68 atm.

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