Answer:
Explanation:
From the given information:
Each of two parents has the genotype brown divided by red
So ;
The man's genotype is : [tex]\mathbf {\dfrac{Brown}{Red}}[/tex]
The woman's genotype is : [tex]\mathbf {\dfrac{Brown}{Red}}[/tex]
This [tex]\mathbf {\dfrac{Brown}{Red}}[/tex] genotype consist of the pair of alleles that determine hair color
Now; we are given an assumption that:
if the child has at least one brown allele, that color will dominate and the child's hair color will be brown.
i.e Brown allele is dominant to Red allele
(a) List the different possible outcomes.
The cross between :
[tex]\mathbf {\dfrac{Brown}{Red}* \mathbf {\dfrac{Brown}{Red}}}[/tex] will produce the following offsprings which is the different possible outcomes.
[tex]= \mathbf {\dfrac{Brown}{Brown} \ \ : \ \ \mathbf {\dfrac{Brown}{Red}} \ \ : \ \ \mathbf {\dfrac{Red}{Brown}} \ \ : \ \ \mathbf {\dfrac{Red}{Red} }}[/tex]
(b) . What is the probability that a child of these parents will have the red divided by red genotype?
The probability that the child of these parents will have [tex]\mathbf {\dfrac{Red}{Red} }}[/tex] is one out of four
i.e
= 1/4
= 0.25
(c) What is the probability that the child will have brown hair color.
We are being told that; if the child has at least one brown allele, that color will dominate and the child's hair color will be brown.
i.e Brown allele is dominant to Red allele
Thus; from above we will see that three of the offsprings have at least one brown allele;
Thus; the probability that the child will have brown hair color is = 3/4
= 0.75
