Respuesta :

[tex]8r-5q=3[/tex] 

[tex]8r-5q=3:q[/tex] 

[tex] -5q=3-8r [/tex]  [tex]|Subtract \ 8r \ from \ both \ sides|[/tex] 

[tex]q= \dfrac{3-8r}{-5} [/tex]  [tex]|Divide \ both \ sides \ by \ -5|[/tex] 

[tex]q= -\dfrac{3-8r}{5} [/tex] 

The solution of the equation for the specified variable (q) is [tex]q = \frac{8r-3}{5}[/tex] OR [tex]q = \frac{8r}{5}- \frac{3}{5}[/tex]

For the given equation, 8r-5q=3, to solve for q means we should make q the subject of the equation. To do this, we rearrange the equation so that q stands alone.

Now, from the given equation

8r-5q=3

[tex]8r-5q=3[/tex]

First, transfer 3 to the left hand side (LHS) of the equation and -5q to the right hand side(RHS) of the equation,

We get

[tex]8r-3=5q[/tex]

[Note that the sign before 3 (+) changes to (-) and the sign before 5q (-) changes to (+)]

Then, we can write that

[tex]5q = 8r-3[/tex]

Now, divide both sides by 5

[tex]\frac{5q}{5} = \frac{8r-3}{5}[/tex]

∴ [tex]q = \frac{8r-3}{5}[/tex]

This can also be written as

[tex]q = \frac{8r}{5}- \frac{3}{5}[/tex]

Hence, the solution of the equation for the specified variable (q) is [tex]q = \frac{8r-3}{5}[/tex] OR [tex]q = \frac{8r}{5}- \frac{3}{5}[/tex]

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