Answer:
advance tickets $30.00
same day tickets $35.00
Step-by-step explanation:
1. In this equation, you are trying to find two values so you must use system of equations. Your two equations would be:
40x +20y = 1900
x + y = 65
x represents the price of advance tickets and y represents the price of same day tickets.
2. Solve the equation by performing elimination using multiplication. Multiple one equation by a constant to get two equations that contain opposite terms.
40x + 20y = 1900
-40(x + y = 65) → -40x + -40y = -2600
3. Add the equations, eliminating one variable. (add -40x + -40y = -2600 to 40x + 20y = 1900)
40x + 20y = 1900
+ -40x + -40y = -2600
Results in: -20y = -700
Solve for y by dviding both sides by -20.
y = 35
4. Substitute the solved value into one of the equations and solve for the remaining variable.
x + 35 = 65
Subtract 35 from both sides to solve for x.
x = 30
The advance tickets were $30.00 and the same day tickets were $35.00.
