Answer:
The minimum thickness t of the wall is 0.00446 mm
Explanation:
Solution
Given that
Pressure =670kPa = 0.670
σ allowable normal stress = 150 MPa
Inner diameter = 2mm
Steel = A516 grade 60
Now,
Since the hoop stress is twice the longitudinal stress, the cylindrical tank is more likely to fail from the hoop stress.
Thus
σ allowable = σₙ = pμ/t
=p (d/2)
150 MPa =0.670MPa * 2/2/t
=0.67/t
t=0.67/150
t =0.00446 mm
