Answer:
a = 25 m/s^2
the magnitude of the acceleration due to gravity on the surface of this planet is 25 m/s^2
Explanation:
Applying the equation of motion;
v^2 = u^2 + 2as ........1
Where;
v = final speed = 20 m/s
u = initial speed = 0 (released from rest)
a = acceleration due to gravity on the planet
s = distance covered = 8.0 m
Since u = 0, equation 1 becomes;
v^2 = 2as
Making a the subject of formula;
a = (v^2)/2s
Substituting the values;
a = (20^2)/(2×8)
a = 25 m/s^2
the magnitude of the acceleration due to gravity on the surface of this planet is 25 m/s^2
