A boy of mass 45kg sits 109cm to the left of the seesaw. Another boy of mass 29000g wants to balance the seesaw. At what distance he needs to sit?

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StaceeLichtenstein StaceeLichtenstein · Answer 1 · 2020-07-08T12:00:26+02:00

Answer:

166 cm

Explanation:

Given :

d1 =109cm

M1= 45kg

M2=29000g = 29 kg

As we know that Newton second law

[tex]Force\ =\ Mass\ *\ Acceleration[/tex]

Here M1= 45kg

and acceleration=[tex]9.81 m/s^{2}[/tex]

Therefore

[tex]F1=45 * 9.81[/tex]

[tex]F1= 441.45 N[/tex]

M2=29000g = 29 kg

Similarly

[tex]F2= 29 * 9.81\\ F2= 284.4 N[/tex]

Now we using the Principal of moments

[tex]F1 * d1 =F2 *d2[/tex]

[tex]441.5 * 109\ =\ 290\ *\ d2\\48,123.5=290 d2\\d2 =165.9[/tex]

~ d2=166 cm