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ΔHFG is dilated by a scale factor of 2 with the center of dilation at point F. Then, it is reflected over line a to create ΔEFI. Based on these transformations, which statement is true? Line segments EG and HI intersect at point F, forming triangles EFI and HFG. Line a intersects with both triangles at point F. segment FG = one half segment FI, segment FH = one half segment FE, and segment HG = one half segment EI; ΔHFG ~ ΔEFI segment FG = segment FI, segment FH = segment FE, and segment HG = segment EI; ΔHFG ~ ΔEFI segment FG = one half segment FE, segment FH = one half segment FI, and segment HG = one halfsegment EI; ΔHFG ~ ΔIFE segment FG = segment FE, segment FH = segment FI and segment HG = segment EI; ΔHFG ~ ΔIFE

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Answer:

segment FG = one half segment FI, segment FH = one half segment FE, and segment HG = one half segment EI; ΔHFG ~ ΔEFI  

Step-by-step explanation:

In the picture attached, the triangles are shown.

After the dilation and reflection, there is proportionality between segment FG and segment FI, segment FH and segment FE, and segment HG  and segment EI. More specifically:

  • FG = 1/2*FI
  • FH = 1/2*FE
  • HG = 1/2*EI
Ver imagen jbiain
InsectaGirl

Answer:

segment FG = one half segment FI, segment FH = one half segment FE, and segment HG = one half segment EI; ΔHFG ~ ΔEFI  

Step-by-step explanation:

In the picture attached, the triangles are shown.

After the dilation and reflection, there is proportionality between segment FG and segment FI, segment FH and segment FE, and segment HG  and segment EI. More specifically:

FG = 1/2*FI

FH = 1/2*FE

HG = 1/2*EI

This answer is right! took the test on FLVS and confirmed it :)

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