The function y=−16x2+v0x models the height of a football in feet x seconds after a player kicks it. In the equation of the function, v0 is the ball's initial velocity in feet per second. The ball hits the ground 2 seconds after the player kicks it.



What is the value of ​v0​?

Respuesta :

Answer:

[tex]\large \boxed{\sf \ \ v_0=32 \ \ }[/tex]

Step-by-step explanation:

Hello,

The equation is

[tex]y=f(x)=-16x^2+v_0 \cdot x[/tex]

The ball hits the ground 2 seconds after the player kicks it, it means that f(2)=0.

We need to find [tex]v_0[/tex]  such that f(2)=0.

[tex]f(2)=-16\cdot 2^2+v_0 \cdot 2=-64+2v_0=0\\\\\text{*** add 64 to both sides ***}\\\\2v_0=64\\\\\text{*** divide by 2 both sides ***} \\\\v_0=\dfrac{64}{2}=32[/tex]

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

Answer:

v0 = 32 ft/s

Step-by-step explanation:

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