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The factorization of x2 + 3x – 4 is modeled with algebra tiles. An algebra tile configuration. 2 tiles are in the Factor 1 spot: 1 is labeled + x, 1 is labeled negative. 5 tiles are in the Factor 2 spot: 1 is labeled + x and 4 are labeled +. 10 tiles are in the Product spot: 1 is labeled + x squared, 1 is labeled negative x, the 4 tiles below + x squared are labeled + x, and the 4 tiles below the negative x tiles are labeled negative. What are the factors of x2 + 3x – 4? (x + 4) and (x – 4) (x + 3) and (x – 4) (x + 4) and (x – 1) (x + 3) and (x – 1)

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Answer:

[tex]\Large \boxed{(x+4)(x-1)}[/tex]

Step-by-step explanation:

Hello,

[tex]x^2+3x-4\\\\\text{*** The product of the zeroes is -4=-1*4 and their sum is -3=-4+1. ***}\\\\\text{*** So we can factorise. ***}\\\\x^2+3x-4=x^2-x+4x-4=x(x-1)+4(x-1)=\large \boxed{(x+4)(x-1)}[/tex]

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The factors of given function are (x + 4) and (x - 1)

To undestand more, check below explanation.

Factors of function:

The modeled for algebra tiles is given as,

                 [tex]f(x)=x^{2} +3x-4[/tex]

We have to find the factors of given function.

Factoring means finding expressions that can be multiplied together to give the given equation.

If a quadratic equation can be factored, it is written as a product of linear terms.

            [tex]f(x)=x^{2} +3x-4\\\\f(x)=x^{2} +4x-x-4\\\\f(x)=x(x+4)-1(x+4)\\\\f(x)=(x+4)(x-1)[/tex]

Hence, the factors of given function are (x + 4) and (x - 1)

Learn more about the factors here:

https://brainly.com/question/25829061